The goals are to:
- demonstrate minimal concrete simplified paging examples that will be useful to those learning paging for the first time
- explain the motivation behind paging
This tutorial was extracted and expanded from this Stack Overflow answer.
Like everything else in programming, the only way to really understand this is to play with minimal examples.
What makes this a "hard" subject is that the minimal example is large because you need to make your own small OS.
Although it is impossible to understand without examples in mind, try to get familiar with the manuals as soon as possible.
Intel describes paging in the Intel Manual Volume 3 System Programming Guide - 325384-056US September 2015 Chapter 4 "Paging".
Specially interesting is Figure 4-4 "Formats of CR3 and Paging-Structure Entries with 32-Bit Paging", which gives the key data structures.
Paging makes it easier to compile and run two programs or threads at the same time on a single computer.
For example, when you compile two programs, the compiler does not know if they are going to be running at the same time or not.
So nothing prevents it from using the same RAM address, say,
0x1234, to store a global variable.
And thread stacks, that must be contiguous and keep growing down until they overwrite each other, are an even bigger issue!
But if two programs use the same address and run at the same time, this is obviously going to break them!
Paging solves this problem beautifully by adding one degree of indirection:
(logical) ------------> (physical) paging
- logical addresses are what userland programs see, e.g. the contents of
mov eax, [rsi].They are often called "virtual" addresses as well.
- physical addresses can be though of the values that go to physical RAM index wires.But keep in mind that this is not 100% true because of further indirections such as:
Compilers don't need to worry about other programs: they just use simple logical addresses.
As far as programs are concerned, they think they can use any address between 0 and 4GiB (2^32,
FFFFFFFF) on 32-bit systems.
The OS then sets up paging so that identical logical addresses will go into different physical addresses and not overwrite each other.
This makes it much simpler to compile programs and run them at the same time.
Paging achieves that goal, and in addition:
- the switch between programs is very fast, because it is implemented by hardware
- the memory of both programs can grow and shrink as needed without too much fragmentation
- one program can never access the memory of another program, even if it wanted to.This is good both for security, and to prevent bugs in one program from crashing other programs.
Or if you like non-funny jokes:
Paging is implemented by the CPU hardware itself.
Paging could be implemented in software, but that would be too slow, because every single RAM memory access uses it!
Operating systems must setup and control paging by communicating to the CPU hardware. This is done mostly via:
- the CR3 register, which tells the CPU where the page table is in RAM memory
- writing the correct paging data structures to the RAM pointed to the CR3 register.Using RAM data structures is a common technique when lots of data must be transmitted to the CPU as it would cost too much to have such a large CPU register.The format of the configuration data structures is fixed _by the hardware_, but it is up to the OS to set up and manage those data structures on RAM correctly, and to tell the hardware where to find them (via
cr3).Then some heavy caching is done to ensure that the RAM access will be fast, in particular using the TLB.Another notable example of RAM data structure used by the CPU is the IDT which sets up interrupt handlers.The OS makes it impossible for programs to change the paging setup directly without going through the OS:
- CR3 cannot be modified in ring 3. The OS runs in ring 0. See also:
- the page table structures are made invisible to the process using paging itself!
Processes can however make requests to the OS that cause the page tables to be modified, notably:
- stack size changes
mmapcalls, see also: https://stackoverflow.com/questions/6988487/what-does-brk-system-call-do/31082353#31082353
The kernel then decides if the request will be granted or not in a controlled manner.
In x86 systems, there may actually be 2 address translation steps:
- first segmentation
- then paging
(logical) ------------------> (linear) ------------> (physical) segmentation paging
The major difference between paging and segmentation is that:
- paging splits RAM into equal sized chunks called pages
- segmentation splits memory into chunks of arbitrary sizes
This is the main advantage of paging, since equal sized chunks make things more manageable by reducing memory fragmentation problems. See also:
Paging came after segmentation historically, and largely replaced it for the implementation of virtual memory in modern OSs.
Paging has become so much more popular that support for segmentation was dropped in x86-64 in 64-bit mode, the main mode of operation for new software, where it only exists in compatibility mode, which emulates IA-32.
This is an example of how paging operates on a _simplified_ version of a x86 architecture to implement a virtual memory space with a
20 | 12address split (4 KiB page size).
This is how the memory could look like in a single level paging scheme:
Links Data Physical address +-----------------------+ 2^32 - 1 | | . . | | +-----------------------+ page0 + 4k | data of page 0 | +---->+-----------------------+ page0 | | | | . . | | | | +-----------------------+ pageN + 4k | | data of page N | | +->+-----------------------+ pageN | | | | | | . . | | | | | | +-----------------------+ CR3 + 2^20 * 4 | +--| entry[2^20-1] = pageN | | +-----------------------+ CR3 + 2^20 - 1 * 4 | | | | . many entires . | | | | +-----------------------+ CR3 + 2 * 4 | +--| entry = page1 | | | +-----------------------+ CR3 + 1 * 4 +-----| entry = page0 | | +-----------------------+ <--- CR3 | | | | . . | | | | +-----------------------+ page1 + 4k | | data of page 1 | +->+-----------------------+ page1 | | . . | | +-----------------------+ 0
- the CR3 register points to the first entry of the page table
- the page table is just a large array with 2^20 page table entries
- each entry is 4 bytes big, so the array takes up 4 MiB
- each page table contains the physical address a page
- each page is a 4 KiB aligned 4KiB chunk of memory that user processes may use
- we have 2^20 table entries. Since each page is 4KiB == 2^12, this covers the whole 4GiB (2^32) of 32-bit memory
Suppose that the OS has setup the following page tables for process 1:and for process 2:
entry index entry address page address present ----------- ------------------ ------------ ------- 0 CR3_1 + 0 * 4 0x00001 1 1 CR3_1 + 1 * 4 0x00000 1 2 CR3_1 + 2 * 4 0x00003 1 3 CR3_1 + 3 * 4 0 ... 2^20-1 CR3_1 + 2^20-1 * 4 0x00005 1
entry index entry address page address present ----------- ----------------- ------------ ------- 0 CR3_2 + 0 * 4 0x0000A 1 1 CR3_2 + 1 * 4 0x12345 1 2 CR3_2 + 2 * 4 0 3 CR3_2 + 3 * 4 0x00003 1 ... 2^20-1 CR3_2 + 2^20-1 * 4 0xFFFFF 1
Before process 1 starts running, the OS sets its
cr3to point to the page table 1 at
When process 1 tries to access a linear address, this is the physical addresses that will be actually accessed:
linear physical --------- --------- 00000 001 00001 001 00000 002 00001 002 00000 003 00001 003 00000 FFF 00001 FFF 00001 000 00000 000 00001 001 00000 001 00001 FFF 00000 FFF 00002 000 00003 000 FFFFF 000 00005 000
To switch to process 2, the OS simply sets
CR3_2, and now the following translations would happen:
linear physical --------- --------- 00000 002 0000A 002 00000 003 0000A 003 00000 FFF 0000A FFF 00001 000 12345 000 00001 001 12345 001 00001 FFF 12345 FFF 00004 000 00003 000 FFFFF 000 FFFFF 000
Step-by-step translation for process 1 of logical address
0x00000001to physical address
- split the linear address into two parts:
| page (20 bits) | offset (12 bits) |So in this case we would have: *page = 0x00000. This part must be translated to a physical location. *offset = 0x001. This part is added directly to the page address, and is not translated: it contains the position _within_ the page.
- look into Page table 1 because
cr3points to it.
- The hardware knows that this entry is located at RAM address
CR3 + 0x00000 * 4 = CR3: *
0x00000because the page part of the logical address is
4because that is the fixed size in bytes of every page table entry
- since it is present, the access is valid
- by the page table, the location of page number
0x00001 * 4K = 0x00001000.
- to find the final physical address we just need to add the offset:
00001 000 + 00000 001 --------- 00001 001because
00001is the physical address of the page looked up on the table and
001is the offset.We shift
00001by 12 bits because the pages are always aligned to 4KiB.The offset is always simply added the physical address of the page.
- the hardware then gets the memory at that physical location and puts it in a register.
Another example: for logical address
- the page part is
00001, and the offset part is
- the hardware knows that its page table entry is located at RAM address:
CR3 + 1 * 4(
1because of the page part), and that is where it will look for it
- it finds the page address
- so the final address is
0x00000 * 4k + 0x001 = 0x00000001
The same linear address can translate to different physical addresses for different processes, depending only on the value inside
Both linear addresses
00002 000from process 1 and
00004 000from process 2 point to the same physical address
00003 000. This is completely allowed by the hardware, and it is up to the operating system to handle such cases.
This often in normal operation because of Copy-on-write (COW), which be explained elsewhere.
Such mappings are sometime called "aliases".
FFFFF 000points to its own physical address
FFFFF 000. This kind of translation is called an "identity mapping", and can be very convenient for OS-level debugging.
What if Process 1 tries to access
0x00003000, which is not present?
The hardware notifies the software via a Page Fault Exception.
When an exception happens, the CPU jumps to an address that the OS had previously registered as the fault handler. This is usually done at boot time by the OS.
This could happen for example due to a programming error:but there are cases where it is not a bug, for example in Linux when:
int *is = malloc(1); is = 1;
- the program wants to increase its stack.It just tries to accesses a certain byte in a given possible range, and if the OS is happy it adds that page to the process address space, otherwise, it sends a signal to the process.
- the page was swapped to disk.The OS will need to do some work behind the processes back to get the page back into RAM.The OS can discover that this is the case based on the contents of the rest of the page table entry, since if the present flag is clear, the other entries of the page table entry are completely left for the OS to to what it wants.On Linux for example, when present = 0:
- if all the fields of the page table entry are 0, invalid address.
- else, the page has been swapped to disk, and the actual values of those fields encode the position of the page on the disk.
In any case, the OS needs to know which address generated the Page Fault to be able to deal with the problem. This is why the nice IA32 developers set the value of
cr2to that address whenever a Page Fault occurs. The exception handler can then just look into
cr2to get the address.
The exact format of table entries is fixed _by the hardware_.
Each page entry can be seen as a
structwith many fields.
The page table is then an array of
On this simplified example, the page table entries contain only two fields:so in this example the hardware designers could have chosen the size of the page table to b
bits function ----- ----------------------------------------- 20 physical address of the start of the page 1 present flag
32as we've used so far.
All real page table entries have other fields, notably fields to set pages to read-only for Copy-on-write. This will be explained elsewhere.
It would be impractical to align things at 21 bits since memory is addressable by bytes and not bits. Therefore, even in only 21 bits are needed in this case, hardware designers would probably choose 32 to make access faster, and just reserve bits the remaining bits for later usage. The actual value on x86 is 32 bits.
Here is a screenshot from the Intel manual image "Formats of CR3 and Paging-Structure Entries with 32-Bit Paging" showing the structure of a page table in all its glory: Figure 2. "x86 page entry format".
The fields are explained in the manual just after.
Why are pages 4KiB anyways?
There is a trade-off between memory wasted in:
- page tables
- extra padding memory within pages
This can be seen with the extreme cases:
- if the page size were 1 byte:
- granularity would be great, and the OS would never have to allocate unneeded padding memory
- but the page table would have 2^32 entries, and take up the entire memory!
- if the page size were 4GiB:
- we would need to swap 4GiB to disk every time a new process becomes active
- the page size would be a single entry, so it would take almost no memory at all
x86 designers have found that 4KiB pages are a good middle ground.
The problem with a single-level paging scheme is that it would take up too much RAM: 4G / 4K = 1M entries _per_ process.
If each entry is 4 bytes long, that would make 4M _per process_, which is too much even for a desktop computer:
ps -A | wc -lsays that I am running 244 processes right now, so that would take around 1GB of my RAM!
For this reason, x86 developers decided to use a multi-level scheme that reduces RAM usage.
The downside of this system is that is has a slightly higher access time, as we need to access RAM more times for each translation.
The algorithmically minded will have noticed that paging requires associative array (like Java
dict()) abstract data structure where:
- the keys are linear pages addresses, thus of integer type
- the values are physical page addresses, also of integer type
The single level paging scheme uses a simple array implementation of the associative array:
and in C pseudo-code it looks like this:
- the keys are the array index
- this implementation is very fast in time
- but it is too inefficient in memory
linear_address = physical_address_0 linear_address = physical_address_1 linear_address = physical_address_2 ... linear_address[2^20-1] = physical_address_N
But there another simple associative array implementation that overcomes the memory problem: an (unbalanced) k-ary tree.
A K-ary tree, is just like a binary tree, but with K children instead of 2.
Using a K-ary tree instead of an array implementation has the following trade-offs:
- it uses way less memory
- it is slower since we have to de-reference extra pointers
In C-pseudo code, a 2-level K-ary tree withand we have the following arrays:
K = 2^10looks like this:
level0 = &level1_0 level1_0 = physical_address_0_0 level1_0 = physical_address_0_1 ... level1_0[2^10-1] = physical_address_0_N level0 = &level1_1 level1_1 = physical_address_1_0 level1_1 = physical_address_1_1 ... level1_1[2^10-1] = physical_address_1_N ... level0[N] = &level1_N level1_N = physical_address_N_0 level1_N = physical_address_N_1 ... level1_N[2^10-1] = physical_address_N_N
and it still contains
directory, which has
2^10elements. Each element contains a pointer to a page table array.
- up to 2^10
pagetablearrays. Each one has
2^104 byte page entries.
2^10 * 2^10 = 2^20possible keys.
K-ary trees can save up a lot of space, because if we only have one key, then we only need the following arrays:
directorywith 2^10 entries
directorywith 2^10 entries
- all other
directory[i]are marked as invalid, don't point to anything, and we don't allocate
pagetablefor them at all
Learned readers will ask themselves: so why use an unbalanced tree instead of balanced one, which offers better asymptotic times https://en.wikipedia.org/wiki/Self-balancing_binary_search_tree?
- the maximum number of entries is small enough due to memory size limitations, that we won't waste too much memory with the root directory entry
- different entries would have different levels, and thus different access times
- tree rotations would likely make caching more complicated
x86's multi-level paging scheme uses a 2 level K-ary tree with 2^10 bits on each level.
Addresses are now split as:
| directory (10 bits) | table (10 bits) | offset (12 bits) |
- the top 10 bits are used to walk the top level of the K-ary tree (
level0)The top table is called a "directory of page tables".
cr3now points to the location on RAM of the page directory of the current process instead of page tables.Page directory entries are very similar to page table entries except that they point to the physical addresses of page tables instead of physical addresses of pages.Each directory entry also takes up 4 bytes, just like page entries, so that makes 4 KiB per process minimum.Page directory entries also contain a valid flag: if invalid, the OS does not allocate a page table for that entry, and saves memory.Each process has one and only one page directory associated to it (and pointed to by
cr3), so it will contain at least
2^10 = 1Kpage directory entries, much better than the minimum 1M entries required on a single-level scheme.
- the next 10 bits are used to walk the second level of the K-ary tree (
level1)Second level entries are also called page tables like the single level scheme.Page tables are only allocated only as needed by the OS.Each page table has only
2^10 = 1Kpage table entries instead of
2^20for the single paging scheme.Each process can now have up to
2^10page tables instead of
2^20for the single paging scheme.
- the offset is again not used for translation, it only gives the offset within a page
One reason for using 10 bits on the first two levels (and not, say,
12 | 8 | 12) is that each Page Table entry is 4 bytes long. Then the 2^10 entries of Page directories and Page Tables will fit nicely into 4Kb pages. This means that it faster and simpler to allocate and deallocate pages for that purpose.
Page directory given to process by the OS:
entry index entry address page table address present ----------- ---------------- ------------------ -------- 0 CR3 + 0 * 4 0x10000 1 1 CR3 + 1 * 4 0 2 CR3 + 2 * 4 0x80000 1 3 CR3 + 3 * 4 0 ... 2^10-1 CR3 + 2^10-1 * 4 0
Page tables given to process by the OS at
PT1 = 0x10000000(
entry index entry address page address present ----------- ---------------- ------------ ------- 0 PT1 + 0 * 4 0x00001 1 1 PT1 + 1 * 4 0 2 PT1 + 2 * 4 0x0000D 1 ... ... 2^10-1 PT1 + 2^10-1 * 4 0x00005 1
Page tables given to process by the OS atwhere
PT2 = 0x80000000(
entry index entry address page address present ----------- --------------- ------------ ------------ 0 PT2 + 0 * 4 0x0000A 1 1 PT2 + 1 * 4 0x0000C 1 2 PT2 + 2 * 4 0 ... 2^10-1 PT2 + 0x3FF * 4 0x00003 1
PT2: initial position of page table 1 and page table 2 for process 1 on RAM.
With that setup, the following translations would happen:
linear 10 10 12 split physical -------- -------------- ---------- 00000001 000 000 001 00001001 00001001 000 001 001 page fault 003FF001 000 3FF 001 00005001 00400000 001 000 000 page fault 00800001 002 000 001 0000A001 00801004 002 001 004 0000C004 00802004 002 002 004 page fault 00B00001 003 000 000 page fault
Let's translate the linear address
0x00801004step by step:
- In binary the linear address is:
0 0 8 0 1 0 0 4 0000 0000 1000 0000 0001 0000 0000 0100
- Grouping as
10 | 10 | 12gives:
0000000010 0000000001 000000000100 0x2 0x1 0x4
page directory entry = 0x2 page table entry = 0x1 offset = 0x4
- The page directory table says that the page table is located at
0x80000 * 4K = 0x80000000. This is the first RAM access of the process.Since the page table entry is
0x1, the hardware looks at entry 1 of the page table at
0x80000000, which tells it that the physical page is located at address
0x0000C * 4K = 0x0000C000. This is the second RAM access of the process.
- Finally, the paging hardware adds the offset, and the final address is
Page faults occur if either a page directory entry or a page table entry is not present.
The Intel manual gives a picture of this translation process in the image "Linear-Address Translation to a 4-KByte Page using 32-Bit Paging": Figure 3. "x86 page translation process"
64 bits is still too much address for current RAM sizes, so most architectures will use less bits.
x86_64 uses 48 bits (256 TiB), and legacy mode's PAE already allows 52-bit addresses (4 PiB). 56-bits is a likely future candidate.
12 of those 48 bits are already reserved for the offset, which leaves 36 bits.
If a 2 level approach is taken, the best split would be two 18 bit levels.
But that would mean that the page directory would have
2^18 = 256Kentries, which would take too much RAM: close to a single-level paging for 32 bit architectures!
Therefore, 64 bit architectures create even further page levels, commonly 3 or 4.
x86_64 uses 4 levels in a
9 | 9 | 9 | 9scheme, so that the upper level only takes up only
2^9higher level entries.
The 48 bits are split equally into two disjoint parts:
----------------- FFFFFFFF FFFFFFFF Top half ----------------- FFFF8000 00000000 Not addressable ----------------- 00007FFF FFFFFFFF Bottom half ----------------- 00000000 00000000
A 5-level scheme is emerging in 2016: https://software.intel.com/sites/default/files/managed/2b/80/5-level_paging_white_paper.pdf which allows 52-bit addresses with 4k pagetables.
Physical address extension.
With 32 bits, only 4GB RAM can be addressed.
This started becoming a limitation for large servers, so Intel introduced the PAE mechanism to Pentium Pro.
To relieve the problem, Intel added 4 new address lines, so that 64GB could be addressed.
Page table structure is also altered if PAE is on. The exact way in which it is altered depends on weather PSE is on or off.
PAE is turned on and off via the
Even if the total addressable memory is 64GB, individual process are still only able to use up to 4GB. The OS can however put different processes on different 4GB chunks.
Page size extension.
Allows for pages to be 4M ( or 2M if PAE is on ) in length instead of 4K.
PSE is turned on and off via the
If either PAE and PSE are active, different paging level schemes are used:
- no PAE and no PSE:
10 | 10 | 12
- no PAE and PSE:
10 | 22.22 is the offset within the 4Mb page, since 22 bits address 4Mb.
- PAE and no PSE:
2 | 9 | 9 | 12The design reason why 9 is used twice instead of 10 is that now entries cannot fit anymore into 32 bits, which were all filled up by 20 address bits and 12 meaningful or reserved flag bits.The reason is that 20 bits are not enough anymore to represent the address of page tables: 24 bits are now needed because of the 4 extra wires added to the processor.Therefore, the designers decided to increase entry size to 64 bits, and to make them fit into a single page table it is necessary reduce the number of entries to 2^9 instead of 2^10.The starting 2 is a new Page level called Page Directory Pointer Table (PDPT), since it _points_ to page directories and fill in the 32 bit linear address. PDPTs are also 64 bits wide.
cr3now points to PDPTs which must be on the fist four 4GB of memory and aligned on 32 bit multiples for addressing efficiency. This means that now
cr3has 27 significative bits instead of 20: 2^5 for the 32 multiples * 2^27 to complete the 2^32 of the first 4GB.
- PAE and PSE:
2 | 9 | 21Designers decided to keep a 9 bit wide field to make it fit into a single page.This leaves 23 bits. Leaving 2 for the PDPT to keep things uniform with the PAE case without PSE leaves 21 for offset, meaning that pages are 2M wide instead of 4M.
The Translation Lookahead Buffer (TLB) is a cache for paging addresses.
Since it is a cache, it shares many of the design issues of the CPU cache, such as associativity level.
This section shall describe a simplified fully associative TLB with 4 single address entries. Note that like other caches, real TLBs are not usually fully associative.
After a translation between linear and physical address happens, it is stored on the TLB. For example, a 4 entry TLB starts in the following state:
valid linear physical ----- ------ -------- > 0 00000 00000 0 00000 00000 0 00000 00000 0 00000 00000
>indicates the current entry to be replaced.
And after a page linear addressand after a second translation of
00003is translated to a physical address
00005, the TLB becomes:
valid linear physical ----- ------ -------- 1 00003 00005 > 0 00000 00000 0 00000 00000 0 00000 00000
valid linear physical ----- ------ -------- 1 00003 00005 1 00007 00009 > 0 00000 00000 0 00000 00000
00003needs to be translated again, hardware first looks up the TLB and finds out its address with a single RAM access
00003 --> 00005.
00000is not on the TLB since no valid entry contains
00000as a key.
When TLB is filled up, older addresses are overwritten. Just like CPU cache, the replacement policy is a potentially complex operation, but a simple and reasonable heuristic is to remove the least recently used entry (LRU).
With LRU, starting from state:adding
valid linear physical ----- ------ -------- > 1 00003 00005 1 00007 00009 1 00009 00001 1 0000B 00003
0000D -> 0000Awould give:
valid linear physical ----- ------ -------- 1 0000D 0000A > 1 00007 00009 1 00009 00001 1 0000B 00003
Using the TLB makes translation faster, because the initial translation takes one access _per TLB level_, which means 2 on a simple 32 bit scheme, but 3 or 4 on 64 bit architectures.
The TLB is usually implemented as an expensive type of RAM called content-addressable memory (CAM). CAM implements an associative map on hardware, that is, a structure that given a key (linear address), retrieves a value.
Mappings could also be implemented on RAM addresses, but CAM mappings may required much less entries than a RAM mapping.
For example, a map in which:
could be stored in a TLB with 4 entries:
- both keys and values have 20 bits (the case of a simple paging schemes)
- at most 4 values need to be stored at each time
linear physical ------ -------- 00000 00001 00001 00010 00010 00011 FFFFF 00000
However, to implement this with RAM, _it would be necessary to have 2^20 addresses_:which would be even more expensive than using a TLB.
linear physical ------ -------- 00000 00001 00001 00010 00010 00011 ... (from 00011 to FFFFE) FFFFF 00000
When the process changes,
cr3change to point to the page table of the new current process.
This creates a problem: the TLB is now filled with a bunch of cached entries for the old process.
A simple and naive solution would be to completely invalidate the TLB whenever the
However, this is would not be very efficient, because it often happens that we switch back to process 1 before process 2 has completely used up the entire TLB cache entries.
The solution for this is to use so called "Address Space Identifiers" (ASID) as mentioned in sources such as:
Basically, the OS assigns a different ASID for each process, and then TLB entries are automatically also tagged with that ASID. This way when the process makes an access, the TLB can determine if a hit is actually for the current process, or if it is an old address coincidence with another process.
The x86 also offers the
invlpginstruction which explicitly invalidates a single TLB entry. Other architectures offer even more instructions to invalidated TLB entries, such as invalidating all entries on a given range.
The Linux kernel makes extensive usage of the paging features of x86 to allow fast process switches with small data fragmentation.
There are also however some features that the Linux kernel might not use, either because they are only for backwards compatibility, or because the Linux devs didn't feel it was worth it yet.
Convert virtual addresses to physical from user space with
/proc/<pid>/pagemapand from kernel space with
Dump all page tables from userspace with
Read and write physical addresses from userspace with
The Linux Kernel reserves two zones of virtual memory:
- one for kernel memory
- one for programs
The exact split is configured by
CONFIG_VMSPLIT_.... By default:
- on 32-bit:
- the bottom 3/4 is program space:
- the top 1/4 is kernel memory:
FFFFFFFF, like this:
------------------ FFFFFFFF Kernel ------------------ C0000000 ------------------ BFFFFFFF Process ------------------ 00000000
- the bottom 3/4 is program space:
- on 64-bit: currently only 48-bits are actually used, split into two equally sized disjoint spaces. The Linux kernel just assigns:
- the bottom part to processes
- the top part to the kernel:
FFFFFFFF FFFFFFFF, like this:
------------------ FFFFFFFF Kernel ------------------ C0000000 (not addressable) ------------------ BFFFFFFF Process ------------------ 00000000
- the bottom part to processes
Kernel memory is also paged.
In previous versions, the paging was continuous, but with HIGHMEM this changed.
There is no clear physical memory split: https://stackoverflow.com/questions/30471742/physical-memory-userspace-kernel-split-on-linux-x86-64
For each process, the virtual address space looks like this:
------------------ 2^32 - 1 Stack (grows down) v v v v v v v v v ------------------ (unmapped) ------------------ Maximum stack size. (unmapped) ------------------- mmap ------------------- (unmapped) ------------------- ^^^^^^^^^^^^^^^^^^^ brk (grows up) ------------------- BSS ------------------- Data ------------------- Text ------------------- ------------------- 0
The kernel maintains a list of pages that belong to each process, and synchronizes that with the paging.
If the program accesses memory that does not belong to it, the kernel handles a page-fault, and decides what to do:
- if it is above the maximum stack size, allocate those pages to the process
- otherwise, send a SIGSEGV to the process, which usually kills it
When an ELF file is loaded by the kernel to start a program with the
execsystem call, the kernel automatically registers text, data, BSS and stack for the program.
mmapareas can be modified by request of the program through the
mmapsystem calls. But the kernel can also deny the program those areas if there is not enough memory.
mmapcan be used to implement
malloc, or the so called "heap".
mmapis also used to load dynamically loaded libraries into the program's memory so that it can access and run it.
Calculating exact addresses Things are complicated by:
- Address Space Layout Randomization.
- the fact that environment variables, CLI arguments, and some ELF header data take up initial stack space: https://unix.stackexchange.com/questions/145557/how-does-stack-allocation-work-in-linux/239323#239323
Why the text does not start at 0: https://stackoverflow.com/questions/14795164/why-do-linux-program-text-sections-start-at-0x0804800-and-stack-tops-start-at-0
Besides a missing page, a very common source of page faults is copy-on-write (COW).
Page tables have extra flags that allow the OS to mark a page a read-only.
Those page faults only happen when a process tries to write to the page, and not read from it.
When Linux forks a process:
- instead of copying all the pages, which is unnecessarily costly, it makes the page tables of the two process point to the same physical address.
- it marks those linear addresses as read-only
- whenever one of the processes tries to write to a page, the makes a copy of the physical memory, and updates the pages of the two process to point to the two different physical addresses
v4.2, look under
There seems to be no structs defined to represent the pages, only macros:
include/asm/page_types.his specially interesting. Excerpt:
#define _PAGE_BIT_PRESENT 0 /* is present */ #define _PAGE_BIT_RW 1 /* writeable */ #define _PAGE_BIT_USER 2 /* userspace addressable */ #define _PAGE_BIT_PWT 3 /* page write through */
CR0, and in particular the
#define X86_CR0_PG_BIT 31 /* Paging */
Paging is done by the Memory Management Unit (MMU) part of the CPU.
It was later integrated into the CPU, but the term MMU still used.
Two level address translation to make OS emulation more efficient.
Peter Cordes mentions that some architectures like MIPS leave paging almost completely in the hands of software: a TLB miss runs an OS-supplied function to walk the page tables, and insert the new mapping into the TLB. In such architectures, the OS can use whatever data structure it wants.
Information about ARM paging can be found at: https://cirosantilli.com/linux-kernel-module-cheat#arm-paging
- rutgers-pxk-416 chapter "Memory management: lecture notes"Good historical review of memory organization techniques used by older OS.
- bovet05 chapter "Memory addressing"Reasonable intro to x86 memory addressing. Missing some good and simple examples.